[Ukr] Uwtig #StandWithUkraine
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Yup, did it yesterday, waiting for the responsetry to send an email to the support.
Yup, did it yesterday, waiting for the responsetry to send an email to the support.
I don't remember anybody ever mentioning of winning one of those , but.... one can still hopeJust today my eyes went on this messag before start feudalife challenge:
"Got room in your Steam library for more PC games?
Enter our MASSIVE Gameplay Giveaway!
You can WIN a secret STEAM KEY if you beat the challenge, from indie games gems to sprawling AAA franchises like Dark souls, Far Cry & more!
If you do not beat the challenge, you still win $$$ GALACREDIT $$$* tospend on our Store!"
Lol anyone has won those AAA games?![]()
I'm sure you can win Dark Souls if you manage to water the whole map or cut all the trees ! Under one minute of course.Lol anyone has won those AAA games?![]()
Just today my eyes went on this messag before start feudalife challenge:
"Got room in your Steam library for more PC games?
Enter our MASSIVE Gameplay Giveaway!
You can WIN a secret STEAM KEY if you beat the challenge, from indie games gems to sprawling AAA franchises like Dark souls, Far Cry & more!
If you do not beat the challenge, you still win $$$ GALACREDIT $$$* tospend on our Store!"
Lol anyone has won those AAA games?![]()
Maybe the title is also known as Dark Souls: (Player) Fall (Off Ladder) Lost (Steam Keys).I saw there are key drops for a game called 'Dark Fall: Lost Souls".
I don't know if it counts, but in January I won Europa Universalis IV (2013), arguably one of the best grand strategy games and one worth some $45-50 on Steam.Just today my eyes went on this messag before start feudalife challenge:
"Got room in your Steam library for more PC games?
Enter our MASSIVE Gameplay Giveaway!
You can WIN a secret STEAM KEY if you beat the challenge, from indie games gems to sprawling AAA franchises like Dark souls, Far Cry & more!
If you do not beat the challenge, you still win $$$ GALACREDIT $$$* tospend on our Store!"
Lol anyone has won those AAA games?![]()
Nice win! The best I won here was Sacred 2 gold.I don't know if it counts, but in January I won Europa Universalis IV (2013), arguably one of the best grand strategy games and one worth some $45-50 on Steam.
Dr. Affirmative, after reading this analysis my mind explodedSo the thing about the watering challenge, i might have figured out the best way to handle this, and it's in fact very easy to understand.
So let's say we have the challenge itself, right?
![]()
The farmer guy representing your character. The black dots representing each of the saplings you have to plant. So what this challenge entails basically is not timing compared to the other challenges. People were always so focused on how to aim or when to click. Wrong. This is a movement based challenge that will dictate your accuracy on how to properly hit every sapling in quick succession without missing. Here's the premise and general structure:
![]()
Obviously i'm using my method, you can simply cut that path halfway instead of going all the way down. Now in order for us to follow that specific path, we basically have to rely on the Digital Pixelation equation starting with \-x+sqrt1−x2\-=sqrt2(2x2−1).
![]()
Answering the fundamentals on how to properly min-max our movement will give us the key on completing this challenge constantly even at 44 seconds (16 malus), but for God's sake please avoid using the X laterals:
![]()
They're not good and it's a rookie mistake abiding by that structure. They're restrictive and honestly a bit of an archaic formula that shows clunky design, probably made by some teen or something cuz... bleh.... like wtf were they thinking?
ax4+bx3+cx2+dx+f=0ax4+bx3+cx2+dx+f=0 ? Hahahahaha piss off
But anyway, stick to the fundamentals:
![]()
And now here's the easy part:
Applying..
Substitutex=cos\alp,\alp∈[0:;π]
\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+1−x2∣=2(2x2−1)\Leftright∣cos\alp+sin\alp∣=2(2cos2\alp−1)
\displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N2cos(\alp−4π)∣=N2cos(2\alp)\Right\alp∈[0;4π]∪[43π;π]
1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0;4π]
Where
\displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp−4π)=cos(2\alp)…
2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[43π;π]
\displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp−4π)=cos(2\alp)…
On the right momentum of your movement would bypass your uncertainty part of your cortex. That hesitation is the main source of why you choke on the movement and not properly hit the plants accurately.
Generally we should've went with the downward s = \sqrt{\frac{1}{N-1} \sum_{i=1}^N (x_i - \overline{x})^2}. equation but that's a bit of a juvenile approach and would not solve anything in the long run.
Once you get the A>D D<A A>D D<A (repeat that like 8 times, the times it takes a sapling to be watered), you then use your middle and your pointing finger to transition on the S>D or S>A movement to the next 2 sets of saplings. You can simply assume your movement as P. So:
P(Y−X=m|Y>X)=∑kP(Y−X=m,X=k|Y>X)=∑kP(Y−X=m|X=k,Y>X)P(X=k|Y>X)=∑kP(Y−k=m|Y>k)P(X=k|Y>X).P(Y−X=m|Y>X)=∑kP(Y−X=m,X=k|Y>X)=∑kP(Y−X=m|X=k,Y>X)P(X=k|Y>X)=∑kP(Y−k=m|Y>k)P(X=k|Y>X).
It's incredibly easy. I would've had an even easier time explaining it if i had the source code of the game so i can accurately pinpoint the parameters in which your character turns left or right (or down of course). But because it is a challenge, we simply have to abide by the limitations of what the game provided us with.
Clearly for the uninitiated, this might look like some jumbled mess of mathematical improbabilities, but once you figure it out, you can remember all of this in like 2 seconds easy. It's a memorable pattern comprised of separate segments designed to train pattern recognition. It was the same equation used for the very early model of the Enigma Machine in 1930, eventually revolutionized by Alan Turin aprox. in 1942 breaking the daily cipher system encrypted by the Germans in WW2.
Wow, didn't read all. Personally I do this challenge easily by doing two plants at the same time, don't know is that better or notSo the thing about the watering challenge, i might have figured out the best way to handle this, and it's in fact very easy to understand.
So let's say we have the challenge itself, right?
![]()
The farmer guy representing your character. The black dots representing each of the saplings you have to plant. So what this challenge entails basically is not timing compared to the other challenges. People were always so focused on how to aim or when to click. Wrong. This is a movement based challenge that will dictate your accuracy on how to properly hit every sapling in quick succession without missing. Here's the premise and general structure:
![]()
Obviously i'm using my method, you can simply cut that path halfway instead of going all the way down. Now in order for us to follow that specific path, we basically have to rely on the Digital Pixelation equation starting with \-x+sqrt1−x2\-=sqrt2(2x2−1).
![]()
Answering the fundamentals on how to properly min-max our movement will give us the key on completing this challenge constantly even at 44 seconds (16 malus), but for God's sake please avoid using the X laterals:
![]()
They're not good and it's a rookie mistake abiding by that structure. They're restrictive and honestly a bit of an archaic formula that shows clunky design, probably made by some teen or something cuz... bleh.... like wtf were they thinking?
ax4+bx3+cx2+dx+f=0ax4+bx3+cx2+dx+f=0 ? Hahahahaha piss off
But anyway, stick to the fundamentals:
![]()
And now here's the easy part:
Applying..
Substitutex=cos\alp,\alp∈[0:;π]
\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+1−x2∣=2(2x2−1)\Leftright∣cos\alp+sin\alp∣=2(2cos2\alp−1)
\displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N2cos(\alp−4π)∣=N2cos(2\alp)\Right\alp∈[0;4π]∪[43π;π]
1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0;4π]
Where
\displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp−4π)=cos(2\alp)…
2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[43π;π]
\displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp−4π)=cos(2\alp)…
On the right momentum of your movement would bypass your uncertainty part of your cortex. That hesitation is the main source of why you choke on the movement and not properly hit the plants accurately.
Generally we should've went with the downward s = \sqrt{\frac{1}{N-1} \sum_{i=1}^N (x_i - \overline{x})^2}. equation but that's a bit of a juvenile approach and would not solve anything in the long run.
Once you get the A>D D<A A>D D<A (repeat that like 8 times, the times it takes a sapling to be watered), you then use your middle and your pointing finger to transition on the S>D or S>A movement to the next 2 sets of saplings. You can simply assume your movement as P. So:
P(Y−X=m|Y>X)=∑kP(Y−X=m,X=k|Y>X)=∑kP(Y−X=m|X=k,Y>X)P(X=k|Y>X)=∑kP(Y−k=m|Y>k)P(X=k|Y>X).P(Y−X=m|Y>X)=∑kP(Y−X=m,X=k|Y>X)=∑kP(Y−X=m|X=k,Y>X)P(X=k|Y>X)=∑kP(Y−k=m|Y>k)P(X=k|Y>X).
It's incredibly easy. I would've had an even easier time explaining it if i had the source code of the game so i can accurately pinpoint the parameters in which your character turns left or right (or down of course). But because it is a challenge, we simply have to abide by the limitations of what the game provided us with.
Clearly for the uninitiated, this might look like some jumbled mess of mathematical improbabilities, but once you figure it out, you can remember all of this in like 2 seconds easy. It's a memorable pattern comprised of separate segments designed to train pattern recognition. It was the same equation used for the very early model of the Enigma Machine in 1930, eventually revolutionized by Alan Turin aprox. in 1942 breaking the daily cipher system encrypted by the Germans in WW2.
you can create a giveaway or put it in the key drops forum.So what do I do in this situation?
not sure what you mean by "clean up" but some people have said that if you write to support and ask, they will delete your codes and give you an empty library - but that was before the newest update where they split the codes into pages, so I'm not sure they delete them anymore, but you could tryHello, is there a way to clean up my gameplay giveaway won list?
Yes, you have to ask support by mail, who will ask their IT team, and they'll wipe every entry. It takes time and a few reminders as it's not a very urgent matter for them, but it's so good to have your account loading in 5 seconds after that... They should add a button so we can do it ourselves (can be dangerous though).not sure what you mean by "clean up" but some people have said that if you write to support and ask, they will delete your codes and give you an empty library - but that was before the newest update where they split the codes into pages, so I'm not sure they delete them anymore, but you could try