Official Feudalife CHALLENGE feedback Thread

BurningPixels

Well-known member
Messages
4,191
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113
Just today my eyes went on this messag before start feudalife challenge:

"Got room in your Steam library for more PC games?

Enter our MASSIVE Gameplay Giveaway!

You can WIN a secret STEAM KEY if you beat the challenge, from indie games gems to sprawling AAA franchises like Dark souls, Far Cry & more!

If you do not beat the challenge, you still win $$$ GALACREDIT $$$* tospend on our Store!"



Lol anyone has won those AAA games? :ROFLMAO:
 

Jer7cho

Well-known member
Messages
2,249
Points
113
Just today my eyes went on this messag before start feudalife challenge:

"Got room in your Steam library for more PC games?

Enter our MASSIVE Gameplay Giveaway!

You can WIN a secret STEAM KEY if you beat the challenge, from indie games gems to sprawling AAA franchises like Dark souls, Far Cry & more!

If you do not beat the challenge, you still win $$$ GALACREDIT $$$* tospend on our Store!"



Lol anyone has won those AAA games? :ROFLMAO:
I don't remember anybody ever mentioning of winning one of those , but.... one can still hope :ROFLMAO:, I won Darksiders tho , don't know if that counts as AAA
 

chaosttc

Well-known member
Messages
473
Points
93
Just today my eyes went on this messag before start feudalife challenge:

"Got room in your Steam library for more PC games?

Enter our MASSIVE Gameplay Giveaway!

You can WIN a secret STEAM KEY if you beat the challenge, from indie games gems to sprawling AAA franchises like Dark souls, Far Cry & more!

If you do not beat the challenge, you still win $$$ GALACREDIT $$$* tospend on our Store!"



Lol anyone has won those AAA games? :ROFLMAO:

I saw there are key drops for a game called 'Dark Fall: Lost Souls".
 

Romanissimus

Member
Messages
18
Points
13
Just today my eyes went on this messag before start feudalife challenge:

"Got room in your Steam library for more PC games?

Enter our MASSIVE Gameplay Giveaway!

You can WIN a secret STEAM KEY if you beat the challenge, from indie games gems to sprawling AAA franchises like Dark souls, Far Cry & more!

If you do not beat the challenge, you still win $$$ GALACREDIT $$$* tospend on our Store!"



Lol anyone has won those AAA games? :ROFLMAO:
I don't know if it counts, but in January I won Europa Universalis IV (2013), arguably one of the best grand strategy games and one worth some $45-50 on Steam.
 

AFFIRMATIVE

Active member
Messages
56
Points
33
So the thing about the watering challenge, i might have figured out the best way to handle this, and it's in fact very easy to understand.

So let's say we have the challenge itself, right?

The farmer guy representing your character. The black dots representing each of the saplings you have to plant. So what this challenge entails basically is not timing compared to the other challenges. People were always so focused on how to aim or when to click. Wrong. This is a movement based challenge that will dictate your accuracy on how to properly hit every sapling in quick succession without missing. Here's the premise and general structure:

Obviously i'm using my method, you can simply cut that path halfway instead of going all the way down. Now in order for us to follow that specific path, we basically have to rely on the Digital Pixelation equation starting with \-x+sqrt1−x2\-=sqrt2(2x2−1).

Answering the fundamentals on how to properly min-max our movement will give us the key on completing this challenge constantly even at 44 seconds (16 malus), but for God's sake please avoid using the X laterals:

They're not good and it's a rookie mistake abiding by that structure. They're restrictive and honestly a bit of an archaic formula that shows clunky design, probably made by some teen or something cuz... bleh.... like wtf were they thinking?
ax4+bx3+cx2+dx+f=0ax4+bx3+cx2+dx+f=0 ? Hahahahaha piss off

But anyway, stick to the fundamentals:

And now here's the easy part:

Applying..

Substitutex=cos\alp,\alp∈[0:;π]
\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+1−x2∣=2(2x2−1)\Leftright∣cos\alp+sin\alp∣=2(2cos2\alp−1)
\displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N2cos(\alp−4π)∣=N2cos(2\alp)\Right\alp∈[0;4π]∪[43π;π]
1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0;4π]
Where
\displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp−4π)=cos(2\alp)…
2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[43π;π]
\displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp−4π)=cos(2\alp)…

On the right momentum of your movement would bypass your uncertainty part of your cortex. That hesitation is the main source of why you choke on the movement and not properly hit the plants accurately.

Generally we should've went with the downward s = \sqrt{\frac{1}{N-1} \sum_{i=1}^N (x_i - \overline{x})^2}. equation but that's a bit of a juvenile approach and would not solve anything in the long run.

Once you get the A>D D<A A>D D<A (repeat that like 8 times, the times it takes a sapling to be watered), you then use your middle and your pointing finger to transition on the S>D or S>A movement to the next 2 sets of saplings. You can simply assume your movement as P. So:

P(Y−X=m|Y>X)=∑kP(Y−X=m,X=k|Y>X)=∑kP(Y−X=m|X=k,Y>X)P(X=k|Y>X)=∑kP(Y−k=m|Y>k)P(X=k|Y>X).P(Y−X=m|Y>X)=∑kP(Y−X=m,X=k|Y>X)=∑kP(Y−X=m|X=k,Y>X)P(X=k|Y>X)=∑kP(Y−k=m|Y>k)P(X=k|Y>X).

It's incredibly easy. I would've had an even easier time explaining it if i had the source code of the game so i can accurately pinpoint the parameters in which your character turns left or right (or down of course). But because it is a challenge, we simply have to abide by the limitations of what the game provided us with.

Clearly for the uninitiated, this might look like some jumbled mess of mathematical improbabilities, but once you figure it out, you can remember all of this in like 2 seconds easy. It's a memorable pattern comprised of separate segments designed to train pattern recognition. It was the same equation used for the very early model of the Enigma Machine in 1930, eventually revolutionized by Alan Turin aprox. in 1942 breaking the daily cipher system encrypted by the Germans in WW2.
 

BurningPixels

Well-known member
Messages
4,191
Points
113
So the thing about the watering challenge, i might have figured out the best way to handle this, and it's in fact very easy to understand.

So let's say we have the challenge itself, right?

The farmer guy representing your character. The black dots representing each of the saplings you have to plant. So what this challenge entails basically is not timing compared to the other challenges. People were always so focused on how to aim or when to click. Wrong. This is a movement based challenge that will dictate your accuracy on how to properly hit every sapling in quick succession without missing. Here's the premise and general structure:

Obviously i'm using my method, you can simply cut that path halfway instead of going all the way down. Now in order for us to follow that specific path, we basically have to rely on the Digital Pixelation equation starting with \-x+sqrt1−x2\-=sqrt2(2x2−1).

Answering the fundamentals on how to properly min-max our movement will give us the key on completing this challenge constantly even at 44 seconds (16 malus), but for God's sake please avoid using the X laterals:

They're not good and it's a rookie mistake abiding by that structure. They're restrictive and honestly a bit of an archaic formula that shows clunky design, probably made by some teen or something cuz... bleh.... like wtf were they thinking?
ax4+bx3+cx2+dx+f=0ax4+bx3+cx2+dx+f=0 ? Hahahahaha piss off

But anyway, stick to the fundamentals:

And now here's the easy part:

Applying..

Substitutex=cos\alp,\alp∈[0:;π]
\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+1−x2∣=2(2x2−1)\Leftright∣cos\alp+sin\alp∣=2(2cos2\alp−1)
\displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N2cos(\alp−4π)∣=N2cos(2\alp)\Right\alp∈[0;4π]∪[43π;π]
1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0;4π]
Where
\displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp−4π)=cos(2\alp)…
2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[43π;π]
\displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp−4π)=cos(2\alp)…

On the right momentum of your movement would bypass your uncertainty part of your cortex. That hesitation is the main source of why you choke on the movement and not properly hit the plants accurately.

Generally we should've went with the downward s = \sqrt{\frac{1}{N-1} \sum_{i=1}^N (x_i - \overline{x})^2}. equation but that's a bit of a juvenile approach and would not solve anything in the long run.

Once you get the A>D D<A A>D D<A (repeat that like 8 times, the times it takes a sapling to be watered), you then use your middle and your pointing finger to transition on the S>D or S>A movement to the next 2 sets of saplings. You can simply assume your movement as P. So:

P(Y−X=m|Y>X)=∑kP(Y−X=m,X=k|Y>X)=∑kP(Y−X=m|X=k,Y>X)P(X=k|Y>X)=∑kP(Y−k=m|Y>k)P(X=k|Y>X).P(Y−X=m|Y>X)=∑kP(Y−X=m,X=k|Y>X)=∑kP(Y−X=m|X=k,Y>X)P(X=k|Y>X)=∑kP(Y−k=m|Y>k)P(X=k|Y>X).

It's incredibly easy. I would've had an even easier time explaining it if i had the source code of the game so i can accurately pinpoint the parameters in which your character turns left or right (or down of course). But because it is a challenge, we simply have to abide by the limitations of what the game provided us with.

Clearly for the uninitiated, this might look like some jumbled mess of mathematical improbabilities, but once you figure it out, you can remember all of this in like 2 seconds easy. It's a memorable pattern comprised of separate segments designed to train pattern recognition. It was the same equation used for the very early model of the Enigma Machine in 1930, eventually revolutionized by Alan Turin aprox. in 1942 breaking the daily cipher system encrypted by the Germans in WW2.
Dr. Affirmative, after reading this analysis my mind exploded :p
 
Messages
10
Points
3
So the thing about the watering challenge, i might have figured out the best way to handle this, and it's in fact very easy to understand.

So let's say we have the challenge itself, right?

The farmer guy representing your character. The black dots representing each of the saplings you have to plant. So what this challenge entails basically is not timing compared to the other challenges. People were always so focused on how to aim or when to click. Wrong. This is a movement based challenge that will dictate your accuracy on how to properly hit every sapling in quick succession without missing. Here's the premise and general structure:

Obviously i'm using my method, you can simply cut that path halfway instead of going all the way down. Now in order for us to follow that specific path, we basically have to rely on the Digital Pixelation equation starting with \-x+sqrt1−x2\-=sqrt2(2x2−1).

Answering the fundamentals on how to properly min-max our movement will give us the key on completing this challenge constantly even at 44 seconds (16 malus), but for God's sake please avoid using the X laterals:

They're not good and it's a rookie mistake abiding by that structure. They're restrictive and honestly a bit of an archaic formula that shows clunky design, probably made by some teen or something cuz... bleh.... like wtf were they thinking?
ax4+bx3+cx2+dx+f=0ax4+bx3+cx2+dx+f=0 ? Hahahahaha piss off

But anyway, stick to the fundamentals:

And now here's the easy part:

Applying..

Substitutex=cos\alp,\alp∈[0:;π]
\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+1−x2∣=2(2x2−1)\Leftright∣cos\alp+sin\alp∣=2(2cos2\alp−1)
\displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N2cos(\alp−4π)∣=N2cos(2\alp)\Right\alp∈[0;4π]∪[43π;π]
1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0;4π]
Where
\displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp−4π)=cos(2\alp)…
2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[43π;π]
\displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp−4π)=cos(2\alp)…

On the right momentum of your movement would bypass your uncertainty part of your cortex. That hesitation is the main source of why you choke on the movement and not properly hit the plants accurately.

Generally we should've went with the downward s = \sqrt{\frac{1}{N-1} \sum_{i=1}^N (x_i - \overline{x})^2}. equation but that's a bit of a juvenile approach and would not solve anything in the long run.

Once you get the A>D D<A A>D D<A (repeat that like 8 times, the times it takes a sapling to be watered), you then use your middle and your pointing finger to transition on the S>D or S>A movement to the next 2 sets of saplings. You can simply assume your movement as P. So:

P(Y−X=m|Y>X)=∑kP(Y−X=m,X=k|Y>X)=∑kP(Y−X=m|X=k,Y>X)P(X=k|Y>X)=∑kP(Y−k=m|Y>k)P(X=k|Y>X).P(Y−X=m|Y>X)=∑kP(Y−X=m,X=k|Y>X)=∑kP(Y−X=m|X=k,Y>X)P(X=k|Y>X)=∑kP(Y−k=m|Y>k)P(X=k|Y>X).

It's incredibly easy. I would've had an even easier time explaining it if i had the source code of the game so i can accurately pinpoint the parameters in which your character turns left or right (or down of course). But because it is a challenge, we simply have to abide by the limitations of what the game provided us with.

Clearly for the uninitiated, this might look like some jumbled mess of mathematical improbabilities, but once you figure it out, you can remember all of this in like 2 seconds easy. It's a memorable pattern comprised of separate segments designed to train pattern recognition. It was the same equation used for the very early model of the Enigma Machine in 1930, eventually revolutionized by Alan Turin aprox. in 1942 breaking the daily cipher system encrypted by the Germans in WW2.
Wow, didn't read all. Personally I do this challenge easily by doing two plants at the same time, don't know is that better or not
 
Last edited:

Nirjor

Well-known member
Messages
806
Points
93
So I won a key but when I tried to redeem it, it said to activate the original game first. So what do I do in this situation? I don't know what the original game is or what dlc my key is for. Would it be possible to change the key from support?
Edit: Found out the base game. It's called "Hacker Evolution Duality".
 
Last edited:

cheerie132

Well-known member
Messages
971
Points
93
Hello, is there a way to clean up my gameplay giveaway won list?
not sure what you mean by "clean up" but some people have said that if you write to support and ask, they will delete your codes and give you an empty library - but that was before the newest update where they split the codes into pages, so I'm not sure they delete them anymore, but you could try
 

Zoliv

Well-known member
Messages
1,961
Points
113
not sure what you mean by "clean up" but some people have said that if you write to support and ask, they will delete your codes and give you an empty library - but that was before the newest update where they split the codes into pages, so I'm not sure they delete them anymore, but you could try
Yes, you have to ask support by mail, who will ask their IT team, and they'll wipe every entry. It takes time and a few reminders as it's not a very urgent matter for them, but it's so good to have your account loading in 5 seconds after that... They should add a button so we can do it ourselves (can be dangerous though).
 
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